document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=773114>Question 773114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the surface area of a clyinder, given its radiusvis 6 feet and its height is 10 feet . use 3..14 for pi and roind to the nearest tenth\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471470 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Surface Area of  a cylinder =<BR>\n" );
document.write( "2*Pi*r^2 + 2*Pi*r*h<BR>\n" );
document.write( "2*Pi*6^2 + 2*Pi*6*10<BR>\n" );
document.write( "226.08 + 376.8<BR>\n" );
document.write( "= 602.9 feet^2<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );