document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66482>Question 66482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The mad Dr. Frankenstein has gathered enough bits and pieces (so to speak) for 2(-1) + 2 (-2)of his creature-to-be.  Write a fraction that represents the amount of his creature that must still be obtained.\r<BR>\n" );
document.write( "\n" );
document.write( "*NOTE the numbers in ( ) should be the exponents but I didn't know how to show that here </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47147 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mad Dr. Frankenstein has gathered enough bits and pieces (so to speak) for 2(-1) + 2 (-2)of his creature-to-be.  Write a fraction that represents the amount of his creature that must still be obtained.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The amount that he already has is (2)^(-1)+(2)^(-2)\r<BR>\n" );
document.write( "\n" );
document.write( "(2)^(-1)=(1/(2^1))=1/2=2/4<BR>\n" );
document.write( "(2)^(-2)=(1/(2^2))=1/4\r<BR>\n" );
document.write( "\n" );
document.write( "Adding these together we get (2/4)+(1/4)=3/4 which is the amount that he already has\r<BR>\n" );
document.write( "\n" );
document.write( "1(creature)-(3/4) creature =(1/4) creature--- the fraction left to get\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps ----ptaylor\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );