document.write( "Question 773301: Please help.\r
\n" ); document.write( "\n" ); document.write( "Robert is five years younger than twice Steven's age. Twice Robert's age five years ago is four more than Steven's age in three years. What are their present ages.?
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Algebra.Com's Answer #471466 by ramkikk66(644)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let Steven's age be x\r\n" );
document.write( "Then Robert's age is (2*x - 5)\r\n" );
document.write( "Analyse the second statement step by step, and form the algebraic expression for\r\n" );
document.write( "each:\r\n" );
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document.write( "1) Robert's age 5 years ago = current age - 5 = 2*x - 5 - 5 = 2*x - 10\r\n" );
document.write( "2) Twice Robert's age 5 years ago = 2*(2*x - 10) = 4*x - 20\r\n" );
document.write( "3) Steven's age in 3 years = x + 3\r\n" );
document.write( "4) So, 4 more than Steven's age in 3 years = x + 3 + 4 = x + 7\r\n" );
document.write( "The above 2 are given to be equal. So the equation is\r\n" );
document.write( "\"4%2Ax+-+20+=+x+%2B+7\"\r\n" );
document.write( "Simplifying\r\n" );
document.write( "\"3%2Ax+=+27\" or \"x+=+9\"\r\n" );
document.write( "Steven's age = \"highlight%289%29\"\r\n" );
document.write( "Robert's age = 2*x - 5 = 18 - 5 = \"highlight%2813%29\"\r\n" );
document.write( "Hope you got it :)\r\n" );
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