document.write( "Question 773301: Please help.\r
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document.write( "Robert is five years younger than twice Steven's age. Twice Robert's age five years ago is four more than Steven's age in three years. What are their present ages.? \n" );
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Algebra.Com's Answer #471466 by ramkikk66(644)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Let Steven's age be x\r\n" ); document.write( "Then Robert's age is (2*x - 5)\r\n" ); document.write( "Analyse the second statement step by step, and form the algebraic expression for\r\n" ); document.write( "each:\r\n" ); document.write( "\r\n" ); document.write( "1) Robert's age 5 years ago = current age - 5 = 2*x - 5 - 5 = 2*x - 10\r\n" ); document.write( "2) Twice Robert's age 5 years ago = 2*(2*x - 10) = 4*x - 20\r\n" ); document.write( "3) Steven's age in 3 years = x + 3\r\n" ); document.write( "4) So, 4 more than Steven's age in 3 years = x + 3 + 4 = x + 7\r\n" ); document.write( "The above 2 are given to be equal. So the equation is\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |