document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66485>Question 66485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> WHICH ONE OF THE FOLLOWING IS TRUE?\r<BR>\n" );
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document.write( "a. The equation (2x-3)2 = 25 is equivalent to 2x-3=5<BR>\n" );
document.write( "b. Every quadratic equation has two distinct numbers in its solution set<BR>\n" );
document.write( "c. The equation 3y-1=11 and 3y-7=5 are equivalent<BR>\n" );
document.write( "d. The equation ax2 + c = 0, a is not equal 0, cannot be solved by the quadratic formula\r<BR>\n" );
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document.write( "**NOTE in both a and d the 2 is meant to be the exponent </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47146 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> WHICH ONE OF THE FOLLOWING IS TRUE? <BR>\n" );
document.write( "a. The equation (2x-3)2 = 25 is equivalent to 2x-3=5<BR>\n" );
document.write( "b. Every quadratic equation has two distinct numbers in its solution set<BR>\n" );
document.write( "c. The equation 3y-1=11 and 3y-7=5 are equivalent<BR>\n" );
document.write( "d. The equation ax2 + c = 0, a is not equal 0, cannot be solved by the quadratic formula <BR>\n" );
document.write( "**NOTE in both a and d the 2 is meant to be the exponent\r<BR>\n" );
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document.write( "a.  (2x-3)^2=25  take sqrt of both sides<BR>\n" );
document.write( " 2x-3=5<BR>\n" );
document.write( "True\r<BR>\n" );
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document.write( "b. Lets look at the standard form for a quadratic equation ax^2+bx+c=0<BR>\n" );
document.write( "The quadratic formula is: x=(-b+or-sqrt(b^2-4ac))/2a<BR>\n" );
document.write( "If a=0, then the formula blows apart<BR>\n" );
document.write( "If (b2-4ac)<0, then the solution set is imaginary<BR>\n" );
document.write( "If b^2=4ac, then we only have one solution, (-b)<BR>\n" );
document.write( "Example:x^2+2x+1 We can factor this quadratic (x+1)(x+1)<BR>\n" );
document.write( "x=-1\r<BR>\n" );
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document.write( "So the answer is False.  \r<BR>\n" );
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document.write( "c.  3y-1=11  add 1 to both sides\r<BR>\n" );
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document.write( "3y-1+1=11+1<BR>\n" );
document.write( "3y=12\r<BR>\n" );
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document.write( "3y-7=5  add 7 to both sides<BR>\n" );
document.write( "3y-7+7=5+7<BR>\n" );
document.write( "3y=12<BR>\n" );
document.write( "True\r<BR>\n" );
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document.write( "d.   ax^2+c =0\r<BR>\n" );
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document.write( " Using the quadratic formula x=(-b+or-sqrt(b^2-4ac))/2a\r<BR>\n" );
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document.write( "x=(-0+or-sqrt(0^2-4ac))/2a simplifying:\r<BR>\n" );
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document.write( "x=(+or-sqrt(-4ac))/2a<BR>\n" );
document.write( "x=(+or-(2sqrt(-ac)/2a<BR>\n" );
document.write( "x=(+or-sqrt(-ac))/a\r<BR>\n" );
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document.write( "False---it can be solved by the quadratic formula and if a or c is negative, then we should have real roots\r<BR>\n" );
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document.write( "Hope this helps------ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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