document.write( "Question 773312: A man is now 5 times as old as his son, four years ago the product of their ages was 52. Find their present ages. \n" ); document.write( "

Algebra.Com's Answer #471447 by Cromlix(4381) $\"\"$ $\"About$

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A man is now 5 times as old as his son.
\n" ); document.write( "M = 5S
\n" ); document.write( "4 years ago the product of their ages = 52
\n" ); document.write( "M - 4 * S - 4 = 52
\n" ); document.write( "Replace M with 5S
\n" ); document.write( "5S - 4 * S - 4 = 52
\n" ); document.write( "5S^2 - 20S - 4S + 16 = 52
\n" ); document.write( "5S^2 - 24S + 16 - 52 = 0
\n" ); document.write( "5S^2 - 24S - 36 = 0
\n" ); document.write( "(5S + 6)(s - 6) = 0
\n" ); document.write( "5S + 6 = 0
\n" ); document.write( "5S = -6
\n" ); document.write( "S = -6/5 (No answer as x < 0)
\n" ); document.write( "s - 6 = 0
\n" ); document.write( "s = 6
\n" ); document.write( "Son = 6 years old
\n" ); document.write( "Father = 30 years old
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "

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