document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=773302>Question 773302</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please could you help me solve this equation, I know the answer is x= -3 but could you explain how to work it out.\r<BR>\n" );
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document.write( "6 - 2x ÷ 3 = 1 - x\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471433 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471433\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6 - 2x ÷ 3 = 1 - x<BR>\n" );
document.write( "1) 18 -2x = 3 -3x     *** multiply both sides of = by 3<BR>\n" );
document.write( "2) 18 +x = 3          *** add 3x to both sides of =<BR>\n" );
document.write( "3)  x = -15<BR>\n" );
document.write( "************** check answer**********<BR>\n" );
document.write( "6 - (2*-15) / 3  =  1 -(-15)<BR>\n" );
document.write( "6 - (-30) / 3 = 16<BR>\n" );
document.write( "16 = 16 </SPAN>\n" );
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