document.write( "Question 773269: Given a circle with radius 5cm and chord AB, measuring 6cm, find the perpendicular distance of \"d\" between AB and the center of the circle. \n" ); document.write( "

Algebra.Com's Answer #471409 by ramkikk66(644) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "

\r\n" );
document.write( "\r\n" );
document.write( "Given a circle with radius 5cm and chord AB, measuring 6cm, find the perpendicular distance of \"d\" between AB and the center of the circle.\r\n" );
document.write( "\r\n" );
document.write( "Ans:\r\n" );
document.write( "Remember that: The perpendicular \"d\" from the center of the circle to the chord, bisects the chord.\r\n" );
document.write( "Let the centre of the circle be O, and the point where d cuts AB be called C.\r\n" );
document.write( "Now:\r\n" );
document.write( "d, CB (half the chord) and OB (radius) form a right triangle with OB as the \r\n" );
document.write( "hypotenuse.\r\n" );
document.write( "OB = 5\r\n" );
document.write( "CB = half of AB = 3\r\n" );
document.write( "Applying Pythagoras theorem\r\n" );
document.write( "d^2 = OB^2 - CB^2 = 25 - 9 = 16\r\n" );
document.write( "Therefore d = 4 cm.\r\n" );
document.write( "Hope you got it :)\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );