document.write( "Question 772845: what is the focus of the conic section 12x+y^2-14y+1=0 \n" ); document.write( "
Algebra.Com's Answer #471404 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! what is the focus of the conic section \n" ); document.write( "12x+y^2-14y+1=0 \n" ); document.write( "complete the square \n" ); document.write( "(y^2-14y+49)-49+1=-12x \n" ); document.write( "(y^2-14y+49)-48=-12x \n" ); document.write( "(y^2-7)^2=-12x+48 \n" ); document.write( "(y^2-7)^2=-12(x-4) \n" ); document.write( "This is an equation of a parabola that opens leftward: \n" ); document.write( "Its basic equation: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex \n" ); document.write( "For given parabola: \n" ); document.write( "vertex: (4,7) \n" ); document.write( "axis of symmetry: y=7 \n" ); document.write( "4p=12 \n" ); document.write( "p=3 \n" ); document.write( "focus: (1,7) \n" ); document.write( " |