document.write( "Question 772845: what is the focus of the conic section 12x+y^2-14y+1=0 \n" ); document.write( "
Algebra.Com's Answer #471404 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
what is the focus of the conic section
\n" ); document.write( "12x+y^2-14y+1=0
\n" ); document.write( "complete the square
\n" ); document.write( "(y^2-14y+49)-49+1=-12x
\n" ); document.write( "(y^2-14y+49)-48=-12x
\n" ); document.write( "(y^2-7)^2=-12x+48
\n" ); document.write( "(y^2-7)^2=-12(x-4)
\n" ); document.write( "This is an equation of a parabola that opens leftward:
\n" ); document.write( "Its basic equation: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "For given parabola:
\n" ); document.write( "vertex: (4,7)
\n" ); document.write( "axis of symmetry: y=7
\n" ); document.write( "4p=12
\n" ); document.write( "p=3
\n" ); document.write( "focus: (1,7)
\n" ); document.write( "
\n" );