document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8485>Question 8485</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am confused concerning inequalities involving absolute value. Could you help me with the problem |3x+7|<7? <BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4714 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4714\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Solve: |3x+7|<7\r<BR>\n" );
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document.write( " A direct way to solve |ax-b| < c if a > 0 and c > 0<BR>\n" );
document.write( " by converting it to  -c < ax-b < c <BR>\n" );
document.write( " or equivalently (b-c)/a < x < (b+c)/a\r<BR>\n" );
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document.write( " Here, a =3, b = -7, c = 7,<BR>\n" );
document.write( " So,    -14/3 < x < 0 or  the interval (-14/3, 0)\r<BR>\n" );
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document.write( " Kenny </SPAN>\n" );
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