document.write( "Question 773257: Michael drove to a friends house at a rate of 40 mph. He returned by the same route at a rate of 45 mph. The driving time for the round trip was 4 hours. What is the distance Michael Traveled?\r
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Algebra.Com's Answer #471384 by ramkikk66(644)\"\" \"About 
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document.write( "Michael drove to a friends house at a rate of 40 mph. He returned by the same route at a rate of 45 mph. The driving time for the round trip was 4 hours. What is the distance Michael Traveled?\r\n" );
document.write( "Ans:\r\n" );
document.write( "Let the distance to the friends house be x miles\r\n" );
document.write( "Distance = Speed * time, or time = Distance / speed.\r\n" );
document.write( "So time taken for driving to the friend's house = x/40\r\n" );
document.write( "And time taken for return = x/45\r\n" );
document.write( "Total time = x/40 + x/45\r\n" );
document.write( "Total time is given to be 4 hours. So we get the equation\r\n" );
document.write( "\"x%2F40+%2B+x%2F45+=+4\" Multipyling by 360 which is the LCM of 40 and 45,\r\n" );
document.write( "\"9x+%2B+8x+=+1440\"\r\n" );
document.write( "\"17x+=+1440\"\r\n" );
document.write( "\"x+=+1440%2F17+=+highlight%2884.71%29\" miles approximately.\r\n" );
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