document.write( "Question 66479: 2x+9x-24/10+10x+6/6=26 \n" ); document.write( "
Algebra.Com's Answer #47138 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! (1) 2x+9x-24/10+10x+6/6=26\r \n" ); document.write( "\n" ); document.write( "First, note that 6/6=1 \n" ); document.write( "And 2x+9x+10x=21x \n" ); document.write( "Also 24/10=12/5 \n" ); document.write( "Now lets rewrite the equation:\r \n" ); document.write( "\n" ); document.write( "(2) 21x-12/5+1=26 Multiply every term by 5 to get rid of the fraction\r \n" ); document.write( "\n" ); document.write( "5(21x)-12(5/5)+1(5)=26(5) simplifying:\r \n" ); document.write( "\n" ); document.write( "105x-12+5=130 add 7 to both sides:\r \n" ); document.write( "\n" ); document.write( "105x-7+7=130+7 \n" ); document.write( "105x=137 \n" ); document.write( "x=137/105\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ck \n" ); document.write( "substitute in (2)\r \n" ); document.write( "\n" ); document.write( "21x-12/5+1=26 \n" ); document.write( "21(137/105)-(12/5)+1=26 \n" ); document.write( "137/5-12/5+5/5=26 \n" ); document.write( "130/5=26 \n" ); document.write( "26=26 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |