document.write( "Question 66479: 2x+9x-24/10+10x+6/6=26 \n" ); document.write( "
Algebra.Com's Answer #47138 by ptaylor(2198)\"\" \"About 
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(1) 2x+9x-24/10+10x+6/6=26\r
\n" ); document.write( "\n" ); document.write( "First, note that 6/6=1
\n" ); document.write( "And 2x+9x+10x=21x
\n" ); document.write( "Also 24/10=12/5
\n" ); document.write( "Now lets rewrite the equation:\r
\n" ); document.write( "\n" ); document.write( "(2) 21x-12/5+1=26 Multiply every term by 5 to get rid of the fraction\r
\n" ); document.write( "\n" ); document.write( "5(21x)-12(5/5)+1(5)=26(5) simplifying:\r
\n" ); document.write( "\n" ); document.write( "105x-12+5=130 add 7 to both sides:\r
\n" ); document.write( "\n" ); document.write( "105x-7+7=130+7
\n" ); document.write( "105x=137
\n" ); document.write( "x=137/105\r
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\n" ); document.write( "\n" ); document.write( "ck
\n" ); document.write( "substitute in (2)\r
\n" ); document.write( "\n" ); document.write( "21x-12/5+1=26
\n" ); document.write( "21(137/105)-(12/5)+1=26
\n" ); document.write( "137/5-12/5+5/5=26
\n" ); document.write( "130/5=26
\n" ); document.write( "26=26
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