document.write( "Question 66466: Okay i dont know what it is with fractions but this one has me stumped, thank you in advance for your help!\r
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document.write( "1+1/5y =2/15y+ 3/2\r
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document.write( "Thanks again! \n" );
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Algebra.Com's Answer #47136 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Okay i dont know what it is with fractions but this one has me stumped, thank you in advance for your help!\r \n" ); document.write( "\n" ); document.write( "(1) 1+1/5y =2/15y+ 3/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply every term by 30y and that will get rid of all fractions:\r \n" ); document.write( "\n" ); document.write( "1(30y)+1(30y)(1/5y)=(30y)(2/15y)+(30y)(3/2) simplifying, we get:\r \n" ); document.write( "\n" ); document.write( "30y+6=4+45y Subtract 45y and 6 from both sides: \n" ); document.write( "30y-45y+6-6=4-6+45y-45y collecting like terms:\r \n" ); document.write( "\n" ); document.write( "-15y=-2 divide both sides by -15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=2/15 \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ck\r \n" ); document.write( "\n" ); document.write( "Substitute y=2/15 into (1):\r \n" ); document.write( "\n" ); document.write( "1+1/(5(2/15))=2/(15(2/15))+3/2=\r \n" ); document.write( "\n" ); document.write( "1+1/(2/3)=2/2+3/2\r \n" ); document.write( "\n" ); document.write( "1+3/2=1+3/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |