document.write( "Question 773143: Solve\r
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\n" ); document.write( "\n" ); document.write( "Log(x+2)+Log(x-1)=Log(70) \n" ); document.write( "

Algebra.Com's Answer #471324 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%28x%2B2%29%2Blog%28x-1%29=log%2870%29\"$ ..write left side as single log\r
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\n" ); document.write( "\n" ); document.write( " $\"log%28%28x%2B2%29%28x-1%29%29=log%2870%29\"$ .....if log same, then\r
\n" ); document.write( "\n" ); document.write( " $\"%28x%2B2%29%28x-1%29=70\"$ is same too; now, solve for $\"x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2-x%2B2x-2=70\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2Bx-2-70=0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2Bx-72=0\"$ ...write $\"x\"$ as $\"9x-8x\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B9x-8x-72=+0\"$ ..group\r
\n" ); document.write( "\n" ); document.write( " $\"%28x%5E2%2B9x%29-%288x%2B72%29=+0\"$ ...factor\r
\n" ); document.write( "\n" ); document.write( " $\"x%28x%2B9%29-8%28x%2B9%29=+0\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%28x-8%29%28x%2B9%29=+0\"$ \r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if $\"%28x-8%29=+0\"$ => $\"x=8\"$ \r
\n" ); document.write( "\n" ); document.write( "if $\"%28x%2B9%29=+0\"$ => $\"x=-9\"$ \r
\n" ); document.write( "\n" ); document.write( "so, we need DISABLED_event_only= > $\"x=8\"$ .....your answer
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