document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=66478>Question 66478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 7(3x+4) = 8(2x+5) + 13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47131 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47131\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7(3x+4) = 8(2x+5) + 13  expand:\r<BR>\n" );
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document.write( "7*3x+7*4=8*2x+8*5+13 multiplyiing the terms, we get\r<BR>\n" );
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document.write( "21x+28=16x+40+13  subtract 16x and 28 from both sides of the equation\r<BR>\n" );
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document.write( "21x-16x-28+28=16x-16x-28+40+13  collecting like terms\r<BR>\n" );
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document.write( "5x=25<BR>\n" );
document.write( "x=5\r<BR>\n" );
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document.write( "ck\r<BR>\n" );
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document.write( "7(3*5+4)=8(2*5+5)+13\r<BR>\n" );
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document.write( "7(19)=8(15)+13<BR>\n" );
document.write( "133=120+13<BR>\n" );
document.write( "133=133\r<BR>\n" );
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document.write( "Hope this helps-----ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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