document.write( "Question 773061: Suppose the following table represents the probability distribution for the number of days that an employee is absent from work during a week selected at random.\r
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document.write( "X = number of days absent\r
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document.write( "X 0 1 2
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document.write( "probability .80 .15 .05\r
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document.write( "a.) what is the probability that an employee could be absent for more than 2 days?\r
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document.write( "B.) what is the expected value for the number of days absent?\r
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document.write( "c.)what is the variance for the number of days absent\r
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document.write( "d.) what is the standard deviation fro the number of days absent? \n" );
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Algebra.Com's Answer #471283 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! Suppose the following table represents the probability distribution for the number of days that an employee is absent from work during a week selected at random.\r \n" ); document.write( "\n" ); document.write( "X = number of days absent\r \n" ); document.write( "\n" ); document.write( "X 0 1 2 \n" ); document.write( "probability .80 .15 .05\r \n" ); document.write( "\n" ); document.write( "a.) what is the probability that an employee could be absent for more than 2 days?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B.) what is the expected value for the number of days absent?\r \n" ); document.write( "\n" ); document.write( "c.)what is the variance for the number of days absent\r \n" ); document.write( "\n" ); document.write( "d.) what is the standard deviation fro the number of days absent?\r \n" ); document.write( "\n" ); document.write( "Answers:\r \n" ); document.write( "\n" ); document.write( "a) 0\r \n" ); document.write( "\n" ); document.write( "b) E(X)= 0(0.8)+1(0.15)+2(0.05) = 0.25\r \n" ); document.write( "\n" ); document.write( "c) V(X) = E(X^2)-(E(X))^2 \r \n" ); document.write( "\n" ); document.write( "E(X^2) =(0^2)(0.8)+(1^2)(0.15)+(2^2)(0.05) = 0.15+0.2 = 0.35\r \n" ); document.write( "\n" ); document.write( "Then V(X) = 0.35- (0.25)^2 = 0.35-0.0625 = 0.2875\r \n" ); document.write( "\n" ); document.write( "d) sd(X) = sqrt(0.2875) \r \n" ); document.write( "\n" ); document.write( "I can help you with more questions at: mthman@gmail.com\r \n" ); document.write( "\n" ); document.write( "Thanks \n" ); document.write( " |