document.write( "Question 66436: A 12 quart cooling system is filled with a solution that is 10% antifreeze. The desired strength of the solution is 40% antifreeze. How many quarts of solution need to be drained and replaced with pure antifreeze to reach the desired strength? \n" ); document.write( "
Algebra.Com's Answer #47128 by josmiceli(19441)\"\" \"About 
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Let x = the amount of mixture I want to remove
\n" ); document.write( "Then .1*x = the amount of antifreeze in the mixture
\n" ); document.write( "Then x = the amount of antifreeze I want to put back in,
\n" ); document.write( "making 12 = the amount of mixture once again
\n" ); document.write( "stated in a formula,
\n" ); document.write( "\"%28.1%2A12+-+.1%2Ax+%2B+x%29+%2F+12+=+.4\"
\n" ); document.write( "\"%281.2+%2B+.9x%29+%2F+12+=+.4\"
\n" ); document.write( "\"4.8+=+1.2+%2B+.9x\"
\n" ); document.write( "\".9x+=+3.6\"
\n" ); document.write( "\"x+=+4\"
\n" ); document.write( "I say that 4 quarts of 10% mixture must be removed and
\n" ); document.write( "replaced with pure antifreeze. Check this
\n" ); document.write( "4 + 8 = 12, so
\n" ); document.write( "\"%284+%2B+.1%2A8%29+%2F+12+=+.4\"
\n" ); document.write( "\"4.8+%2F+12+=+.4\"
\n" ); document.write( "\".4+=+.4\"
\n" ); document.write( "
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