document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=773043>Question 773043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose it is 11 to 5 against a person who is now 38 years of age living till he is 73 and 5 against 3 against B now 43 living till he is 78.Find the chance that at least one of these persons will be alive 35 years hence. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471273 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A and B those persons\r<BR>\n" );
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document.write( "P(A live 35 years more) = 1-11/16\r<BR>\n" );
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document.write( "P(B live 35 years more) = 1- 5/8\r<BR>\n" );
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document.write( "P( at least A or B live 35 years more) =  1-(1-P(A))(1-P(B)) = 1-(11/16)(5/8)\r<BR>\n" );
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document.write( "= 1-55/128 = 73/128\r<BR>\n" );
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document.write( "Answer: 73/128\r<BR>\n" );
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document.write( "I can help you with more questions at: mthman@gmail.com\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
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