document.write( "Question 773008: If the product is 48. Find the two consecutive factors and write them as an algebraic expression \n" ); document.write( "

Algebra.Com's Answer #471250 by josgarithmetic(39617) $\"\"$ $\"About$

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\"Consecutive factors\"?\r
\n" ); document.write( "\n" ); document.write( "n and n+1 as factors?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "n(n+1)=48
\n" ); document.write( "n^2+n=48
\n" ); document.write( "n^2+n-48=0\r
\n" ); document.write( "\n" ); document.write( "Check discriminant: $\"%281%5E2-4%2A%28-48%29%29%3C%3E0\"$
\n" ); document.write( "n will be nonwhole, but irrational.
\n" ); document.write( "Did you leave something off the problem?\r
\n" ); document.write( "\n" ); document.write( "Maybe $\"xy=48\"$ for some two whole number factors x and y.
\n" ); document.write( "These are your only positive possibilities to get product 48:
\n" ); document.write( " $\"1%2A48\"$
\n" ); document.write( " $\"2%2A24\"$
\n" ); document.write( " $\"3%2A12\"$
\n" ); document.write( " $\"6%2A8\"$ ________This might be what you want, if consecutive EVEN integers. \n" ); document.write( "

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