document.write( "Question 772718: How many quarts of pure alcohol must be added to 10 quarts of 10% alcohol solution to obtain a mixture which is 25% alcohol?
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Algebra.Com's Answer #471235 by modi.kk91(20) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " let pure alcohol 100%
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\n" ); document.write( "\n" ); document.write( " x*100%+10*10%=25%(x+10)
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\n" ); document.write( "\n" ); document.write( " after solving
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\n" ); document.write( "\n" ); document.write( " x=2 quarts \r
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\n" ); document.write( "\n" ); document.write( " by allegation and mixture \r
\n" ); document.write( "\n" ); document.write( " let pure alcohol be 100%\r
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\n" ); document.write( "\n" ); document.write( " 10% 100%\r
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\n" ); document.write( "\n" ); document.write( " 25% \r
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\n" ); document.write( "\n" ); document.write( "100-25=75 and 25-10=15\r
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\n" ); document.write( "\n" ); document.write( "ratio=75:15=5:1\r
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\n" ); document.write( "\n" ); document.write( " 5:1::10:x\r
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\n" ); document.write( "\n" ); document.write( " x=2
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