document.write( "Question 282968: how much water should be added to a radiator that contains 10 gallons of an 80% solution antifreeze solution to dilute it to a 50% antifreeze solution? \n" ); document.write( "

Algebra.Com's Answer #471233 by modi.kk91(20) $\"\"$ $\"About$

You can put this solution on YOUR website!
allegation mixture
\n" ); document.write( " \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " 0% 80%\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " 50%\r
\n" ); document.write( "\n" ); document.write( " 80-50=30 and 50-0=50\r
\n" ); document.write( "\n" ); document.write( "ratio=30:50=====3:5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " 3:5::x:10\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " X=6 gallons
\n" ); document.write( " second method\r
\n" ); document.write( "\n" ); document.write( " let the added water be x at 0%\r
\n" ); document.write( "\n" ); document.write( " x*0%+10*80%=50%(x+10)\r
\n" ); document.write( "\n" ); document.write( " 800=50x+500
\n" ); document.write( "
\n" ); document.write( " 300=50x\r
\n" ); document.write( "\n" ); document.write( " x=6 gallons\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );