document.write( "Question 66413: Business and finance. In planning for a new item, a manufacturer assumes that
\n" ); document.write( "the number of items produced x and the cost in dollars C of producing these items
\n" ); document.write( "are related by a linear equation. Projections are that 100 items will cost $10,000 to
\n" ); document.write( "produce and that 300 items will cost $22,000 to produce. Find the equation that
\n" ); document.write( "relates C and x.
\n" ); document.write( "

Algebra.Com's Answer #47122 by ankor@dixie-net.com(22740)\"\" \"About 
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Business and finance. In planning for a new item, a manufacturer assumes that
\n" ); document.write( "the number of items produced x and the cost in dollars C of producing these
\n" ); document.write( " items are related by a linear equation. Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce.
\n" ); document.write( "Find the equation that relates C and x.
\n" ); document.write( ":
\n" ); document.write( "Let's do the problem using the variables x & y: Cost=y
\n" ); document.write( ":
\n" ); document.write( "Find the slope: m = (y2-y1)/(x2-x1)
\n" ); document.write( "In our problem x1 = 100, y1 = 10000; x2 = 300, y2 = 22000
\n" ); document.write( ":
\n" ); document.write( "Find the slope (m)
\n" ); document.write( "m = \"%28%2822000-10000%29%29%2F%28%28300-100%29%29\" = \"12000%2F200\" = 60 is the slope
\n" ); document.write( ":
\n" ); document.write( "Now use the point/slope equation: y - y1 = m(x - x1)
\n" ); document.write( "y - 10000 = 60(x - 100)
\n" ); document.write( "y - 10000 = 60x - 6000
\n" ); document.write( "y = 60x - 6000 + 10000
\n" ); document.write( "y = 60x + 4000
\n" ); document.write( ":
\n" ); document.write( "Substituting \"Cost\" for y we have:
\n" ); document.write( "Cost = 60x + 4000
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