document.write( "Question 66413: Business and finance. In planning for a new item, a manufacturer assumes that
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document.write( "the number of items produced x and the cost in dollars C of producing these items
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document.write( "are related by a linear equation. Projections are that 100 items will cost $10,000 to
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document.write( "produce and that 300 items will cost $22,000 to produce. Find the equation that
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document.write( "relates C and x. \n" );
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Algebra.Com's Answer #47122 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Business and finance. In planning for a new item, a manufacturer assumes that \n" ); document.write( "the number of items produced x and the cost in dollars C of producing these \n" ); document.write( " items are related by a linear equation. Projections are that 100 items will cost $10,000 to produce and that 300 items will cost $22,000 to produce. \n" ); document.write( "Find the equation that relates C and x. \n" ); document.write( ": \n" ); document.write( "Let's do the problem using the variables x & y: Cost=y \n" ); document.write( ": \n" ); document.write( "Find the slope: m = (y2-y1)/(x2-x1) \n" ); document.write( "In our problem x1 = 100, y1 = 10000; x2 = 300, y2 = 22000 \n" ); document.write( ": \n" ); document.write( "Find the slope (m) \n" ); document.write( "m = \n" ); document.write( ": \n" ); document.write( "Now use the point/slope equation: y - y1 = m(x - x1) \n" ); document.write( "y - 10000 = 60(x - 100) \n" ); document.write( "y - 10000 = 60x - 6000 \n" ); document.write( "y = 60x - 6000 + 10000 \n" ); document.write( "y = 60x + 4000 \n" ); document.write( ": \n" ); document.write( "Substituting \"Cost\" for y we have: \n" ); document.write( "Cost = 60x + 4000 \n" ); document.write( " |