document.write( "Question 772949: A $4000 investment at an annual simple interest rate of 3.9% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interest. How much was invested at 6.5%?
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Algebra.Com's Answer #471208 by stanbon(75887)\"\" \"About 
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A $4000 investment at an annual simple interest rate of 3.9% earned as much interest after one year as another investment in an account that earned 6.5% annual simple interest. How much was invested at 6.5%?
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\n" ); document.write( "4000(1+0.039*1) = x(1+0.065*1)
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\n" ); document.write( "4000(1.039) = x(1.065)
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\n" ); document.write( "x = $3902.35
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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