document.write( "Question 772793: A cannonball is shot into the air with a velocity of 60ft/sec. at what time will the cannonball first reach a height of 36ft, using the equation below?
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Algebra.Com's Answer #471111 by Edwin McCravy(20054) $\"\"$ $\"About$

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h=-16t^2 + 60t
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document.write( "Plug in 36 for h, then simplify and solve that quadratic \r\n" );
document.write( "equation for t\r\n" );
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document.write( "You'll get two answers, t=3/4 and t=3.\r\n" );
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document.write( "It will be at a height of 36 feet first in 3/4ths of a second\r\n" );
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document.write( "It will also be at a height of 36 feet again in 3 seconds.\r\n" );
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document.write( "One answer is when the cannonball is going up, and the other \r\n" );
document.write( "answer is when it is coming down.\r\n" );
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document.write( "He wants the answer when it FIRST was at that height (when going up),\r\n" );
document.write( "so it's 3/4 of a second.\r\n" );
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document.write( "Edwin

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