document.write( "Question 772675: A group of 30 tourists paid a total of $686 in bus fares. If the adult fare was $28 and children paid half fare, how many adults were in the group? \n" ); document.write( "
Algebra.Com's Answer #471102 by pakhi(24)![]() ![]() You can put this solution on YOUR website! Let the number of adults in the group be A. \n" ); document.write( "Let the number of children in the group be C.\r \n" ); document.write( "\n" ); document.write( "Therefore according to the problem \n" ); document.write( "Condition 1 A child's fare was half of that of an adult's fare i.e. 28/2= $14. \n" ); document.write( " \n" ); document.write( "Condition 2 Total number of tourists were equal to 30 \n" ); document.write( " A + C = 30 or C = 30 - A ------------------(1)\r \n" ); document.write( "\n" ); document.write( "Condition 3 Total bus fare was $686 which was equal to the bus fares of A adults @ $28 each plus the fares of C children @ $14 each \n" ); document.write( " 28A + 14C = 686 \n" ); document.write( " Putting the value of C from equation 1 we get \n" ); document.write( " 28A + 14(30 - A) = 686 \n" ); document.write( " or 28A + 420 - 14A = 686 \n" ); document.write( " or 14A = 686 - 420 = 266 \n" ); document.write( " or A = 266/14 = 19 \n" ); document.write( " Also C= 30 - A = 30 - 19 - 11\r \n" ); document.write( "\n" ); document.write( "So the number of adults in the bus was 19 and the number of children was 11. \n" ); document.write( " \n" ); document.write( " |