document.write( "Question 310597: How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution
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document.write( "to get a 20% solution? \n" );
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Algebra.Com's Answer #471075 by modi.kk91(20)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( " 10% 80%\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 20%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "80-20=60 20-10=10\r \n" ); document.write( "\n" ); document.write( " ratio=6:1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 6:1::x:50\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " x=300liter \n" ); document.write( " |