document.write( "Question 324803: A chemist has 35% NaCl solution and 50% NaCl solution. How many liters of each should he mix to get 10L of NaCl solution with 40% base concentration? \n" ); document.write( "

Algebra.Com's Answer #471073 by modi.kk91(20) $\"\"$ $\"About$

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first method \r
\n" ); document.write( "\n" ); document.write( " let liter of 35%solution=x
\n" ); document.write( " liter of 50% solution= 10-x\r
\n" ); document.write( "\n" ); document.write( " 35%x+50%(10-x)=40%10
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\n" ); document.write( " 35x+500-50x=400
\n" ); document.write( " 100=15x
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\n" ); document.write( " x=100/15 at 35%
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\n" ); document.write( " 10-100/15=50/100 at 50%
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\n" ); document.write( "\n" ); document.write( "second method\r
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\n" ); document.write( "\n" ); document.write( " 35% 50%
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\n" ); document.write( "\n" ); document.write( " 40%\r
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\n" ); document.write( "\n" ); document.write( "50-40=10 and 40-35=5\r
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\n" ); document.write( "\n" ); document.write( "ratio=2:1======2x+1x=3x\r
\n" ); document.write( "\n" ); document.write( " ans 2x=20/3
\n" ); document.write( " 1x=10/3\r
\n" ); document.write( "\n" ); document.write( " 3x=10
\n" ); document.write( " x=10/3\r
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