document.write( "Question 323455: A 40% dye solution is to be mixed with a dye solution to get 120 liters of a 50% solution. How many liters of the 40% and 70% solutions will be needed? \n" ); document.write( "
Algebra.Com's Answer #471068 by modi.kk91(20)![]() ![]() You can put this solution on YOUR website! very easy solution by allegation rule\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 40% 70%\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 50%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 70-50=20 and 50-40=10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ratio=2:1=====2x+1x=3x \n" ); document.write( " ans=2x=80 \n" ); document.write( " 1x=40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 3x=120\r \n" ); document.write( "\n" ); document.write( " x=120/3=40 \n" ); document.write( " |