document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321728>Question 321728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 280 mL solution is 20% salt. How much water should be added to make the solution 14% salt? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #471060 by </B><A HREF=/tutors/aboutme.mpl?userid=modi.kk91><B>modi.kk91(20)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=modi.kk91><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=modi.kk91><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=471060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> here given 20%salt of 280 ml<BR>\n" );
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document.write( " then salt=20*280/100=56 salt<BR>\n" );
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document.write( " let added water be x<BR>\n" );
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document.write( "  then <BR>\n" );
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document.write( "   56/280+x=14/100\r<BR>\n" );
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document.write( "     1680=14x<BR>\n" );
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document.write( "ans x=1680/40===120 </SPAN>\n" );
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