document.write( "Question 772570: how do you factor: 2t^7+54t^4 \n" ); document.write( "

Algebra.Com's Answer #471008 by KMST(5328) $\"\"$ $\"About$

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$\"2t%5E7%2B54t%5E4=2t%5E4%28t%5E3%2B27%29\"$ taking out $\"2t%5E4\"$ as a common factor.
\n" ); document.write( "Then, a sum of cubes is a special product of the form
\n" ); document.write( " $\"%28a%5E2-ab%2Bb%5E2%29%28a%2Bb%29=a%5E3%2Bb%5E3\"$
\n" ); document.write( "and since $\"t%5E3%2B27=t%5E3%2B3%5E3\"$ , $\"t%5E3%2B27=%28t%2B3%29%28t%5E2-3t%2B3%5E2%29\"$
\n" ); document.write( "So,
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