document.write( "Question 772608: 19.) Solve for x algebraically.\r
\n" ); document.write( "\n" ); document.write( "ln(2x+3)-ln(x-5)= 2\r
\n" ); document.write( "\n" ); document.write( "Here's what i have started.\r
\n" ); document.write( "\n" ); document.write( "ln(2x+3)/(x-5)=2\r
\n" ); document.write( "\n" ); document.write( "I'm not sure where to go past here.
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Algebra.Com's Answer #471003 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Solve for x algebraically.\r
\n" ); document.write( "\n" ); document.write( "ln(2x+3)-ln(x-5)= 2\r
\n" ); document.write( "\n" ); document.write( "Here's what i have started.\r
\n" ); document.write( "\n" ); document.write( "ln(2x+3)/(x-5)=2\r
\n" ); document.write( "\n" ); document.write( "I'm not sure where to go past here.
\n" ); document.write( "----------------
\n" ); document.write( "\"ln%28%282x%2B3%29%2F%28x-5%29%29=2+\" Make it clear that it's the ln of the quotient.
\n" ); document.write( "\"%282x%2B3%29%2F%28x-5%29+=+e%5E2+\"
\n" ); document.write( "e^2 is a constant. Can you finish it?
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