document.write( "Question 772516: Solve with Substitution
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document.write( "5x+4y=12
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document.write( "3x+4y=4
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document.write( "Answer should look like (x,y) \n" );
document.write( "
Algebra.Com's Answer #470995 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 5x + 4y = 12 \n" ); document.write( "3x + 4y = 4 \n" ); document.write( ":\ \n" ); document.write( "using the 2nd equation solve for y \n" ); document.write( "3x + 4y = 4 \n" ); document.write( "4y = -3x + 4 \n" ); document.write( "Divide both sides by 4 \n" ); document.write( "y = -.75x + 1 \n" ); document.write( "In the first equation, replace y with (-.75x+1) \n" ); document.write( "5x + 4(-.75x+1) = 12 \n" ); document.write( "5x - 3x + 4 = 12 \n" ); document.write( "2x = 12 - 4 \n" ); document.write( "2x = 8 \n" ); document.write( "x = 4 \n" ); document.write( ": \n" ); document.write( "You can find find y, check solutions in both equations \n" ); document.write( " |