document.write( "Question 66395: multiply:\r
\n" ); document.write( "\n" ); document.write( "-3a^2b 14a^3b^2
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\n" ); document.write( "35a^5 -9b^4\r
\n" ); document.write( "\n" ); document.write( "If this was simpler I could figure it out, but with so many letters in it I have just become lost! Thank you for the help!!!!\r
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Algebra.Com's Answer #47099 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Multiply:
\n" ); document.write( "\"%28%28-3a%5E2b%29%2F35a%5E5%29%2A%28%2814a%5E3b%5E2%29%2F-9b%5E4%29%29\" Ok, let's take it one step at-a-time.
\n" ); document.write( "First look at the numbers.
\n" ); document.write( "Do you see that you can cancel a -3 in the numerator of the first fraction and the -9 in the denominator of the second fraction, leaving a 3 in the denominator of the second fraction?
\n" ); document.write( "\"%28%28a%5E2b%29%2F%2835a%5E5%29%29%2A%28%2814a%5E3b%5E2%29%2F%283b%5E4%29%29\" Now do you see that the 14 and the 35 are both divisible by 7? Then let's divide them by 7.
\n" ); document.write( "\"%28a%5E2b%2F5a%5E5%29%2A%282a%5E3b%5E2%2F3b%5E4%29\" Now we can look at the variables, a and b.
\n" ); document.write( "Remember the rules for dividing factors with exponents?
\n" ); document.write( "If the base is the same (in this case, the bases are a and b), you subtract the exponents. Let's do the a's first and see what we get!
\n" ); document.write( "\"%28a%5E%282-2%29b%2F5a%5E%285-2%29%29%2A%282a%5E3b%5E2%2F3b%5E4%29\" Simplifying this a bit and remembering that \"a%5E0+=+1\"
\n" ); document.write( "\"%28b%2F5a%5E3%29%2A%282a%5E3b%5E2%2F3b%5E4%29\" Now we can do the same thing with the \"a%5E3\"s
\n" ); document.write( "\"%28b%2F5%29%2A%282b%5E2%2F3b%5E4%29\" Now do the b's
\n" ); document.write( "\"%28b%2F5%29%2A%282%2F3b%5E2%29\" Finally, cancel the b's and simplify.
\n" ); document.write( "\"%281%2F5%29%2A%282%2F3b%29\" = \"2%2F15b\"...and there it is!
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