document.write( "Question 772444: A mixture contains 12 Ibs of substance A and 96 Ibs of Substance B. What % is A of the mixture? \n" ); document.write( "

Algebra.Com's Answer #470875 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
What you want is:
\n" ); document.write( " $\"+%28+A+%2F+%28+A+%2B+B+%29+%29%2A100+\"$ = % of mixture
\n" ); document.write( "---------------------
\n" ); document.write( " $\"++12+%2F+%28+12+%2B+96+%29+%2A100++=+%28+12%2F108+%29%2A100+\"$
\n" ); document.write( " $\"+%28+12%2F108+%29+=+1%2F9+\"$
\n" ); document.write( " $\"+%28+1%2F9%29%2A100+=+11.111+\"$
\n" ); document.write( "A is 11.111 % of the mixture
\n" ); document.write( "( this is 11 plus the continuing fraction
\n" ); document.write( ".111. . . )
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