document.write( "Question 772444: A mixture contains 12 Ibs of substance A and 96 Ibs of Substance B. What % is A of the mixture? \n" ); document.write( "
Algebra.Com's Answer #470873 by Cromlix(4381)\"\" \"About 
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12lbs + 96lbs = 108lbs
\n" ); document.write( "12/108 * 100 = 11.1%
\n" ); document.write( "Substance A is 11.1% of the mixture.
\n" ); document.write( "Hope this helps.
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