document.write( "Question 772440: Given:AB=BC
\n" );
document.write( "Prove AC=2BC
\n" );
document.write( "1. AB=BC (Given)
\n" );
document.write( "2. AB+BC=AC (Segment Addition Postulate)
\n" );
document.write( "3. BC+BC=AC (Substitution Property of Equality)
\n" );
document.write( "4. 2BC=AC (Distributive Property)
\n" );
document.write( "5. AC=2BC (Identity)\r
\n" );
document.write( "\n" );
document.write( "Identify the hypothesis, Argument and Conclusion. \n" );
document.write( "
Algebra.Com's Answer #470872 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "The hypothesis is the what you are trying to prove. \r \n" ); document.write( "\n" ); document.write( "in your case, the hypothesis is \n" ); document.write( "\n" ); document.write( "The conclusion is the last statement in your proof. \n" ); document.write( "in your case, \n" ); document.write( "\n" ); document.write( "For a properly completed direct proof, the |