document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=772421>Question 772421</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Which sum yields   4-6a/x-2?\r<BR>\n" );
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document.write( "2. Perform the indicated operations and simplify the following expression: 5a+3/a^2+13a+12 - 2a-3/a^2+13a+12\r<BR>\n" );
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document.write( "3.Solve for k in  k/k+1=3/k^2-k-2\r<BR>\n" );
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document.write( "4. Your textbook says that the focal length f of a lens is given by the lensmaker's formula 1/F=0.6(1/R1+1/R2) where r1 and r2 are the radii of the two circular surfaces. If those radii are 4 and 6 respectively, find f. \r<BR>\n" );
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document.write( "5. Solve the following equation : 3t-5/t-1=2+2t/1-t\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470860 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ \frac{k}{k\ +\ 1}\ =\ \frac{3}{k^2\ -\ k\ -\ 2}\">\r<BR>\n" );
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document.write( "Factor the denominator in the RHS.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  \ \ \ \ \ \ \ \ \ \ \frac{k}{k\ +\ 1}\ =\ \frac{3}{(k\ +\ 1)(k\ -\ 2)}\">\r<BR>\n" );
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document.write( "Apply the LCD\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  \ \ \ \ \ \ \ \ \ \ \frac{k(k\ -\ 2)}{(k\ +\ 1)(k\ -\ 2)}\ =\ \frac{3}{(k\ +\ 1)(k\ -\ 2)}\">\r<BR>\n" );
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document.write( "Multiply by the common denominator:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  \ \ \ \ \ \ \ \ \ \ k(k\ -\ 2)\ =\ 3\">\r<BR>\n" );
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document.write( "Distribute, collect all terms in the LHS\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  \ \ \ \ \ \ \ \ \ \ k^2\ -\ 2k\ -\ 3\ =\ 0\">\r<BR>\n" );
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document.write( "Factor and solve the quadratic:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  \ \ \ \ \ \ \ \ \ \ (k\ -\ 3)(k\ +\ 1)\ =\ 0\">\r<BR>\n" );
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document.write( "Hence\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  \ \ \ \ \ \ \ \ \ \ k\ =\ 3\">\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE  \ \ \ \ \ \ \ \ \ \ k\ =\ -1\">\r<BR>\n" );
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document.write( "But -1 causes a zero denominator and therefore is excluded from the domain of both the LHS and RHS functions i the original equation.  Therefore exclude -1 as a root.  The solution set consists of the single value 3.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "<font face=\"Math1\" size=\"+2\">Egw to Beta kai to Sigma</font><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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