document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=750706>Question 750706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the circle that is tangent to the line x-1=0 and x-6=0, and passes through the point (2,2). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470820 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since our two lines are parallel, the circle's diameter must be 6-1=5 (and so r=5/2)\r<BR>\n" );
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document.write( "This means that the x-coordinate of the center must 1+5/2=7/2\r<BR>\n" );
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document.write( "Next we can write:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-7%2F2%29%5E2%2B%28y-k%29%5E2=%285%2F2%29%5E2 ALIGN=MIDDLE  ALT=\"%28x-7%2F2%29%5E2%2B%28y-k%29%5E2=%285%2F2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "after solving we determine that k=0.\r<BR>\n" );
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document.write( "therefore...\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-7%2F2%29%5E2%2By%5E2=%285%2F2%29%5E2 ALIGN=MIDDLE  ALT=\"%28x-7%2F2%29%5E2%2By%5E2=%285%2F2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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