document.write( "Question 772378: The given consecutive integers are 4,5, and 6. If I square the 2nd integer, the answer will be 25. Then, if I multiply the 1st and 3rd integer, the answer will be 24, Which is 1 number less that the squared integer. That happens every time I do the same method in consecutive integers. How is that possible? \n" ); document.write( "
Algebra.Com's Answer #470819 by josgarithmetic(39620)\"\" \"About 
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Interesting question!
\n" ); document.write( "Try to generalize and try the same process.\r
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\n" ); document.write( "\n" ); document.write( "Three consecutive integers, n, n+1, n+2.\r
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\n" ); document.write( "\n" ); document.write( "SQUARE THE SECOND INTEGER.
\n" ); document.write( "\"%28n%2B1%29%5E2\"
\n" ); document.write( "\"n%5E2%2B2n%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "MULTIPLY THE FIRST AND THIRD INTEGERS.
\n" ); document.write( "\"n%28n%2B2%29\"
\n" ); document.write( "\"n%5E2%2B2n\"\r
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\n" ); document.write( "\n" ); document.write( "FIND THE DIFFERENCE BETWEEN THOSE TWO RESULTS.
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\n" ); document.write( "\n" ); document.write( "n can be ANY integer. The process will still work.
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