document.write( "Question 772378: The given consecutive integers are 4,5, and 6. If I square the 2nd integer, the answer will be 25. Then, if I multiply the 1st and 3rd integer, the answer will be 24, Which is 1 number less that the squared integer. That happens every time I do the same method in consecutive integers. How is that possible? \n" ); document.write( "
Algebra.Com's Answer #470819 by josgarithmetic(39620)![]() ![]() ![]() You can put this solution on YOUR website! Interesting question! \n" ); document.write( "Try to generalize and try the same process.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Three consecutive integers, n, n+1, n+2.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SQUARE THE SECOND INTEGER. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "MULTIPLY THE FIRST AND THIRD INTEGERS. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "FIND THE DIFFERENCE BETWEEN THOSE TWO RESULTS. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "n can be ANY integer. The process will still work. \n" ); document.write( " |