document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=772368>Question 772368</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A two digit number, whose sum of digits is ten, will be 36 less than the original number when the digits are reversed. What is the original number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470808 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A two digit number, whose sum of digits is ten, will be 36 less than the original number when the digits are reversed. What is the original number?<BR>\n" );
document.write( "***<BR>\n" );
document.write( "let u=units digit<BR>\n" );
document.write( "let t=tens digit<BR>\n" );
document.write( "u+t=10<BR>\n" );
document.write( "u=10-t<BR>\n" );
document.write( "..<BR>\n" );
document.write( "10t+u=10u+t+36<BR>\n" );
document.write( "10t+10-t=10(10-t)+t+36<BR>\n" );
document.write( "10t+10-t=100-10t+t+36<BR>\n" );
document.write( "10t+10-t=100-10t+t+36<BR>\n" );
document.write( "18t=126<BR>\n" );
document.write( "t=7<BR>\n" );
document.write( "u=10-t=3<BR>\n" );
document.write( "original number=73 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );