document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=772304>Question 772304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square has an area of 27 units. If the perimeter of the square is equal to the perimeter if the equilateral triangle, find the area of the equilateral triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470795 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First main goal is find the side length of the equilateral triangle.  \r<BR>\n" );
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document.write( "SQUARE:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=27=w%5E2 ALIGN=MIDDLE  ALT=\"27=w%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > for w being length of side of the square.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w=sqrt%2827%29 ALIGN=MIDDLE  ALT=\"w=sqrt%2827%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w=3%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"w=3%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Perimeter is then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2A3%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"4%2A3%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Perimeter is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"12%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Let t = side length of equilateral triangle.  Given is the perimeter is the same as that of the square, so, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3t=4w ALIGN=MIDDLE  ALT=\"3t=4w\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3t=12%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"3t=12%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t=12%2Asqrt%283%29%2F3 ALIGN=MIDDLE  ALT=\"t=12%2Asqrt%283%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28t=4%2Asqrt%283%29%29 ALIGN=MIDDLE  ALT=\"highlight%28t=4%2Asqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "WHAT WE KNOW ABOUT EQUILATERAL TRIANGLE\r<BR>\n" );
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document.write( "The altitude splits the triangle into two congruent right triangles of hypotenuse t and one leg of t/2.  The other leg, the altitude of the equilateral triangle, is then some a, a=sqrt(t^2-(t/2)^2);<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=t%2A%28sqrt%283%29%2F2%29 ALIGN=MIDDLE  ALT=\"a=t%2A%28sqrt%283%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "AREA OF EQUILATERAL TRIANGLES:<BR>\n" );
document.write( "Base times height then divided by 2;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%28t%2F2%29%28a%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29%28t%2F2%29%28a%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%28t%2F2%29%28t%2Asqrt%283%29%2F2%29 ALIGN=MIDDLE  ALT=\"%281%2F2%29%28t%2F2%29%28t%2Asqrt%283%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t%5E2%28sqrt%283%29%2F8%29 ALIGN=MIDDLE  ALT=\"t%5E2%28sqrt%283%29%2F8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Finally substitute for value of t:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%284%2F3%29sqrt%2827%29%29%28sqrt%283%29%2F8%29 ALIGN=MIDDLE  ALT=\"%28%284%2F3%29sqrt%2827%29%29%28sqrt%283%29%2F8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%5E4%2A3%2A3%2Asqrt%283%29%29%2F%289%2A2%5E3%29 ALIGN=MIDDLE  ALT=\"%282%5E4%2A3%2A3%2Asqrt%283%29%29%2F%289%2A2%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2A3%2Asqrt%283%29 ALIGN=MIDDLE  ALT=\"2%2A3%2Asqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%286%2Asqrt%283%29%29 ALIGN=MIDDLE  ALT=\"highlight%286%2Asqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >___________Final Answer\r<BR>\n" );
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document.write( "NOTE: Draw a picture will help. </SPAN>\n" );
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