document.write( "Question 66376: absolute value of x-1 -0.5 is less than or equal to (1/2)x+5\r
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Algebra.Com's Answer #47078 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! absolute value of x-1 -0.5 is less than or equal to (1/2)x+5 \n" ); document.write( "-------------- \n" ); document.write( "|x-1|-0.5 <=(1/2)x+5 \n" ); document.write( "|x-1|<=(1/2)x+5.5 \n" ); document.write( "-------------------- \n" ); document.write( "Comment: The absolute can have two meanings: \n" ); document.write( "If x>=1 |x-1|=x-1 \n" ); document.write( "If x<1 |x-1|=-(x-1) \n" ); document.write( "--------------------- \n" ); document.write( "So, \n" ); document.write( "If x>=1, you get x-1<=(1/2)x+5.5 \n" ); document.write( "(1/2)x<=6.5 \n" ); document.write( "x<=13 \n" ); document.write( "----------- \n" ); document.write( "If x<1, you get -(x-1)<=(1/2)x+5.5 \n" ); document.write( "-x+1<=(1/2)x+5.5 \n" ); document.write( "(3/2)x>=-4.5 \n" ); document.write( "x>=-3 \n" ); document.write( "-------------- \n" ); document.write( "Final solution: \n" ); document.write( "-3<=x<=13 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |