document.write( "Question 771795: If sinx=3/5 and x is in quadrant 2, then what is the value of tan x/2? I cannot tell if i should use arcsin to solve this I am very confused \n" ); document.write( "
Algebra.Com's Answer #470728 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! If sinx=3/5 and x is in quadrant 2, then what is the value of tan x/2? I cannot tell if i should use arcsin to solve this I am very confused \n" ); document.write( "*** \n" ); document.write( "You are working with a 3-4-5 reference right triangle in quadrant II where sin>0, cos<0, tan<0. \n" ); document.write( "sinx=3/5 \n" ); document.write( "cosx=-4/5 \n" ); document.write( "Identity: tan(x/2)=(sinx)/(1+cosx) \n" ); document.write( "=(3/5)/(1-4/5)=3/5/1/5=3 \n" ); document.write( "tan(x/2)=3 \n" ); document.write( ".. \n" ); document.write( "Calculator check: \n" ); document.write( "tanx=-3/4 \n" ); document.write( "x=143.13º \n" ); document.write( "x/2=71.565 \n" ); document.write( "tan 71.565º≈2.999... \n" ); document.write( "exact value=3 \n" ); document.write( " |