document.write( "Question 8476: My question is solving 7 ln 9x = 49 , and expressing it in the term of e.If you could help me with this it would be greatly appreciated. \n" ); document.write( "

Algebra.Com's Answer #4707 by prince_abubu(198) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+7+ln%289x%29+=+49+\"$ <----- Start here\r
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\n" ); document.write( "\n" ); document.write( " $\"+ln%289x%29+=+7+\"$ <---- Divide both sides by 7\r
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\n" ); document.write( "\n" ); document.write( " $\"+e%5E7+=+9x+\"$ <----- translate the natural log equation to the exponential equivalent. Remember that $\"+ln%289x%29+\"$ really is $\"+log%28e%2C9x%29+\"$ . The way that I translate it is this: The base of the log becomes the base in the exponent form. What used to be on the right side of the equals sign (in the log equation) becomes the power that the new base is raised to. What you're ln'ning or log'ging goes to the opposite side of the equals sign from the base and exponent.\r
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\n" ); document.write( "\n" ); document.write( " $\"+e%5E7%2F9+=+x+\"$ <---- Divide both sides by 9. You've got an answer now that is in terms of e. \n" ); document.write( "

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