document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=772029>Question 772029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the formula for this pattern? <BR>\n" );
document.write( "10, 9, 6, 1, -6\r<BR>\n" );
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document.write( "I understand that each number decreases by an odd number that is 2 more than the previous one, but I'm uncertain about how to write that as an algebra formula. I came up with 2n-(n+1), but it only worked for the first one. If you could explain how you got an answer, that would also be very welcome. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470648 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "What is the formula for this pattern? <BR>\n" );
document.write( "10, 9, 6, 1, -6\r<BR>\n" );
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document.write( "I understand that each number decreases by an odd number that is 2 more than the previous one, but I'm uncertain about how to write that as an algebra formula. I came up with 2n-(n+1), but it only worked for the first one. If you could explain how you got an answer, that would also be very welcome.\r<BR>\n" );
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document.write( "Formula, based on pattern: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28a%5Bn%5D+=+a%5B1%5D+-+%28n+-+1%29%5E2%29 ALIGN=MIDDLE  ALT=\"highlight_green%28a%5Bn%5D+=+a%5B1%5D+-+%28n+-+1%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, with:\r<BR>\n" );
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document.write( "\"n\" being the term number\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bn%5D ALIGN=MIDDLE  ALT=\"a%5Bn%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > being term number n's value \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5B1%5D ALIGN=MIDDLE  ALT=\"a%5B1%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > being the 1st term, or 10\r<BR>\n" );
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document.write( "Using the above pattern rule, or formula, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bn%5D+=+a%5B1%5D+-+%28n+-+1%29%5E2 ALIGN=MIDDLE  ALT=\"a%5Bn%5D+=+a%5B1%5D+-+%28n+-+1%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, term number 6, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5B6%5D+=+10+-+%286+-+1%29%5E2 ALIGN=MIDDLE  ALT=\"a%5B6%5D+=+10+-+%286+-+1%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > ------ <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5B6%5D+=+10+-+5%5E2 ALIGN=MIDDLE  ALT=\"a%5B6%5D+=+10+-+5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > ------ <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5B6%5D+=+10+-+25 ALIGN=MIDDLE  ALT=\"a%5B6%5D+=+10+-+25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28a%5B6%5D+=+-+15%29 ALIGN=MIDDLE  ALT=\"highlight%28a%5B6%5D+=+-+15%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You can check other terms' values using this formula!! \r<BR>\n" );
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document.write( "Further help is available, online or in-person, for a fee, obviously. Send comments, “thank-yous,” and inquiries to “D” at MathMadEzy@aol.com </SPAN>\n" );
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