document.write( "Question 772029: What is the formula for this pattern?
\n" ); document.write( "10, 9, 6, 1, -6\r
\n" ); document.write( "\n" ); document.write( "I understand that each number decreases by an odd number that is 2 more than the previous one, but I'm uncertain about how to write that as an algebra formula. I came up with 2n-(n+1), but it only worked for the first one. If you could explain how you got an answer, that would also be very welcome.
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Algebra.Com's Answer #470645 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Here is something you should find:\r
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\n" ); document.write( "\n" ); document.write( "\"10-9=1\"
\n" ); document.write( "\"10-6=4\"
\n" ); document.write( "\"10-1=9\"
\n" ); document.write( "\"10-%28-6%29=16\"\r
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\n" ); document.write( "\n" ); document.write( "Do you notice that the difference between each term and the FIRST term is a square? (the first term is 10)\r
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\n" ); document.write( "\n" ); document.write( "Make a data table with column headings to identify index, the term, expression for difference from 10, and expression to show how that difference is composed.\r
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\n" ); document.write( "\n" ); document.write( "You should see, for index n, each term is \"10-%28n-1%29%5E2\".
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