document.write( "Question 772041: if sinA - cotA =0, find:-
\n" ); document.write( "1) angle A
\n" ); document.write( "2)1-tan^2A/1+tan^2A
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Algebra.Com's Answer #470636 by Alan3354(69443)\"\" \"About 
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if sinA - cotA =0, find:-
\n" ); document.write( "1) angle A
\n" ); document.write( "2)1-tan^2A/1+tan^2A
\n" ); document.write( "================================
\n" ); document.write( "sinA - cotA =0
\n" ); document.write( "sinA - cosA/sinA = 0
\n" ); document.write( "sin^2 - cos = 0
\n" ); document.write( "1-cos^2 - cos = 0
\n" ); document.write( "cos^2 + cos - 1 = 0
\n" ); document.write( "Sub x for cos(A)
\n" ); document.write( "x^2 + x - 1 = 0
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B-1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A-1=5\".
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\n" ); document.write( " Discriminant d=5 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-1%2B-sqrt%28+5+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%281%29%2Bsqrt%28+5+%29%29%2F2%5C1+=+0.618033988749895\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%281%29-sqrt%28+5+%29%29%2F2%5C1+=+-1.61803398874989\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B1x%2B-1\" can be factored:
\n" ); document.write( " \"1x%5E2%2B1x%2B-1+=+%28x-0.618033988749895%29%2A%28x--1.61803398874989%29\"
\n" ); document.write( " Again, the answer is: 0.618033988749895, -1.61803398874989.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B-1+%29\"

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\n" ); document.write( "A =~ 51.8273 degs\r
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