document.write( "Question 771914: Find a if the point (3,a) is on the line that passes through (-2,7) and (5,-3). \n" ); document.write( "
Algebra.Com's Answer #470593 by MathLover1(20850)\"\" \"About 
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first find equation of a line that passes through (-2,7) and (5,-3)\r
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Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 7) and (x2, y2) = (5, -3).
\n" ); document.write( " Slope a is .
\n" ); document.write( " Intercept is found from equation \"a%2Ax%5B1%5D%2Bb+=+y%5B1%5D\", or \"-1.42857142857143%2A-2+%2Bb+=+4.14285714285714\". From that,
\n" ); document.write( " intercept b is \"b=y%5B1%5D-a%2Ax%5B1%5D\", or \"b=7--1.42857142857143%2A-2+=+4.14285714285714\".
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\n" ); document.write( " y=(-1.42857142857143)x + (4.14285714285714)
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\n" ); document.write( " Your graph:
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\n" ); document.write( "\n" ); document.write( "\"y=-1.43x+%2B+4.14\"\r
\n" ); document.write( "\n" ); document.write( "if the point (3,a), means \"x=3\" and \"y=a\", plug it in equation above\r
\n" ); document.write( "\n" ); document.write( "\"a=-1.43%2A3+%2B+4.14\"\r
\n" ); document.write( "\n" ); document.write( "\"a=-4.29+%2B+4.14\"\r
\n" ); document.write( "\n" ); document.write( "\"a=-0.15\"\r
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