document.write( "Question 771931: I have been stuck on this question for about 45 minutes can somebody please help me?
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document.write( "Problem :A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dimes as nickels and 8 fewer nickels than quarters. How much money is in the bank? Thank You! \n" );
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Algebra.Com's Answer #470564 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dimes as nickels and 8 fewer nickels than quarters. How much money is in the bank? \n" ); document.write( ". \n" ); document.write( "Let q = number of quarters \n" ); document.write( "then from \"8 fewer nickels than quarters\": \n" ); document.write( "q-8 = number of nickels \n" ); document.write( "and from \"twice as many dimes as nickels\" \n" ); document.write( "2(q-8) = number of dimes \n" ); document.write( ". \n" ); document.write( "q + q-8 + 2(q-8) = 44 \n" ); document.write( "q + q-8 + 2q-16 = 44 \n" ); document.write( "4q -8 -16 = 44 \n" ); document.write( "4q -24 = 44 \n" ); document.write( "4q = 68 \n" ); document.write( "q = 16 \n" ); document.write( ". \n" ); document.write( "amount in bank: \n" ); document.write( ".25q + .05(q-8) + .10(2(q-8)) \n" ); document.write( ".25(16) + .05(16-8) + .10(2(16-8)) \n" ); document.write( ".25(16) + .05(8) + .10(2(8)) \n" ); document.write( ".25(16) + .05(8) + .10(16) \n" ); document.write( ".25(16) + .05(8) + .10(16) \n" ); document.write( "4 + .40 + 1.60 \n" ); document.write( "$6.00 \n" ); document.write( " \n" ); document.write( " |