document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=280025>Question 280025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the missing sides and angles in the right triangle, where a is the side across from angle A, b across from B, and c across from the right angle. (Round your answers to 3 decimal places.)<BR>\n" );
document.write( "c = 18, A = 20°<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470553 by </B><A HREF=/tutors/aboutme.mpl?userid=arKed><B>arKed(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arKed><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=arKed><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Solving for side a using Trigonometric function sine:<BR>\n" );
document.write( "a=18Sin20<BR>\n" );
document.write( "a= 6.156\r<BR>\n" );
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document.write( "Since it was a right triangle, therefore C= 90 degrees\r<BR>\n" );
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document.write( "Solving for B:<BR>\n" );
document.write( "B=180-(C+A)<BR>\n" );
document.write( "B=180-(90+20)<BR>\n" );
document.write( "B=70 degrees\r<BR>\n" );
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document.write( "Solving for side b using trigonometric function sine:<BR>\n" );
document.write( "b=18sin70<BR>\n" );
document.write( "b=16.914 </SPAN>\n" );
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