document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=771878>Question 771878</A>: <I><SPAN STYLE=\"word-break: break-all;\">  find the value of the unknown<BR>\n" );
document.write( "the gradient of AB is 4, where A= (2,1) and B (5,y)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #470530 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=470530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using the gradient formula:<BR>\n" );
document.write( "y2 - y1/x2 - x1<BR>\n" );
document.write( "y - 1/5 - 2<BR>\n" );
document.write( "y-1/3<BR>\n" );
document.write( "y - 1/3  = 4<BR>\n" );
document.write( "Cross multiply<BR>\n" );
document.write( "y - 1 = 12<BR>\n" );
document.write( "y = 13<BR>\n" );
document.write( "Coordinates for B = (5,13)<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );